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Forum Maschinenbau Rostock • Thema anzeigen - 39.1

39.1

39.1

Beitragvon Majan » Mo 3. Jan 2011, 18:32

Mal zum vergleichen:
a) y=(c1+c2x)+e^4x

b)y=C1e^x + C2e^-x + C3sin(x) + C4cos(x)
Majan
 
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Re: 39.1

Beitragvon HayTxa » Mo 3. Jan 2011, 20:53

HayTxa
 
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Re: 39.1

Beitragvon Majan » Mo 3. Jan 2011, 22:22

jep hast recht!
Majan
 
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Re: 39.1

Beitragvon Rico » Do 6. Jan 2011, 17:40

hmm, aber man kommt doch nur auf eine Nullstelle und dadurch doch auch nur auf e^4x
also y=c1*e^4x
Rico
 
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Re: 39.1

Beitragvon Richter88 » Fr 7. Jan 2011, 21:03

das polynom is 2. grades...also muss du entweder 2 einfache nullstellen oder eine zweifache nullstelle haben..da du nur eine hast ist die 2-fache nullstelle :)

mal was anderes wie kommt ihr auf λ=i als lösung für die charakt. gleichung?
Richter88
 
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Re: 39.1

Beitragvon Gunnar » Sa 8. Jan 2011, 08:50

(ʌ ̂ 4 -1) = (ʌ³+ʌ²+ʌ+1) * (ʌ-1), damit ist ʌ_1=1. Zweite NS (ʌ³+ʌ²+ʌ+1)=0, durch Probieren ʌ_2=-1 finden (Kann man natürlich auch schon so in der Ausgangsgleichung sehen) Dann Plynomdivision (ʌ³+ʌ²+ʌ+1):(ʌ+1)=(ʌ²+1) Und die Nullstellen für (ʌ²+1) sind ʌ_3=i und ʌ_4=-i.
Zuletzt geändert von Gunnar am Sa 8. Jan 2011, 15:23, insgesamt 1-mal geändert.
Gunnar
 
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Re: 39.1

Beitragvon Richter88 » Sa 8. Jan 2011, 12:22

ahh..ja klar! danke!
Richter88
 
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